Find the mass of a photon emitted by a sodium lamp (wavelength $\lambda = 5890 \ \mathring{A}$). How many times is this mass compared to the mass of an electron?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The mass of a photon is given by the relation $m = \frac{h}{\lambda c}$.
Given: $h = 6.626 \times 10^{-34} \ J \cdot s$,$\lambda = 5890 \ \mathring{A} = 5890 \times 10^{-10} \ m$,$c = 3 \times 10^8 \ m/s$.
$m = \frac{6.626 \times 10^{-34}}{5890 \times 10^{-10} \times 3 \times 10^8} = 3.75 \times 10^{-36} \ kg$.
The mass of an electron is $m_e = 9.11 \times 10^{-31} \ kg$.
Ratio $= \frac{m}{m_e} = \frac{3.75 \times 10^{-36}}{9.11 \times 10^{-31}} \approx 4.11 \times 10^{-6}$ times.

Explore More

Similar Questions

Electromagnetic radiations of frequency $\nu$ consist of a stream of particles called photons. Which of the following statements is / are true about photons:

$A$ photon of wavelength $6630 \mathring{A}$ is incident on a totally reflecting surface. The momentum delivered by the photon is equal to

The photoelectric effect shows:

The energy of one mole of photons of radiation of frequency $2 \times 10^{12} \ Hz$ in $J \ mol^{-1}$ is $.....$ (Nearest integer) (Given: $h = 6.626 \times 10^{-34} \ Js$,$N_A = 6.022 \times 10^{23} \ mol^{-1}$)

The frequency of yellow light having wavelength $600 \ nm$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo