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(B) To find the median,we first calculate the cumulative frequency $(cf)$:ClassFrequency $(f)$Cumulative Frequency $(cf)$$0-20$$5$$5$$20-40$$15$$20$$4

Vedclass · Accepted Answer

$50$

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(B) To find the median,we first calculate the cumulative frequency $(cf)$:ClassFrequency $(f)$Cumulative Frequency $(cf)$$0-20$$5$$5$$20-40$$15$$20$$40-60$$20$$40$$60-80$$18$$58$$80-100$$2$$60$Total frequency $N = 60$. So,$N/2 = 60/2 = 30$.The cumulative frequency just greater than $30$ is $40$,which corresponds to the median class $40-60$.Here,lower limit $l = 40$,class size $h = 20$,frequency of median class $f = 20$,and cumulative frequency of the class preceding the median class $cf = 20$.Using the median formula: $	ext{Median} = l + \left( \frac{\frac{N}{2} - cf}{f} ight) 	imes h$$	ext{Median} = 40 + \left( \frac{30 - 20}{20} ight) 	imes 20$$	ext{Median} = 40 + \left( \frac{10}{20} ight) 	imes 20 = 40 + 10 = 50$.

Class	$65-85$	$85-105$	$105-125$	$125-145$	$145-165$	$165-185$	$185-205$
Frequency	$4$	$5$	$13$	$20$	$14$	$8$	$4$

Find the median of the following frequency distribution:
Class $0-20$ $20-40$ $40-60$ $60-80$ $80-100$
Frequency $5$ $15$ $20$ $18$ $2$

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The mean of the following frequency distribution is $46$. Find the missing frequency $f$.

Class $0-20, 20-40, 40-60, 60-80, 80-100, 100-120$

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Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$

Frequency $4$ $5$ $13$ $20$ $14$ $8$ $4$

$Z - M = \ldots \ldots \ldots \times (M - \bar{x})$

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Class	$0-20$	$20-40$	$40-60$	$60-80$	$80-100$
Frequency	$5$	$15$	$20$	$18$	$2$

Class	$0-20, 20-40, 40-60, 60-80, 80-100, 100-120$
Frequency	$10, f, 7, 6, 5, 4$

Find the median of the following frequency distribution:Class$0-20$$20-40$$40-60$$60-80$$80-100$Frequency$5$$15$$20$$18$$2$