Find the median of the following frequency di | vedclass

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(A) To find the median,we first calculate the cumulative frequency $(cf)$:| Class | Frequency $(f)$ | Cumulative Frequency $(cf)$ || :--- | :--- | :--

Vedclass · Accepted Answer

$153.79$

Vedclass · Answer

(A) To find the median,we first calculate the cumulative frequency $(cf)$:| Class | Frequency $(f)$ | Cumulative Frequency $(cf)$ || :--- | :--- | :--- || $110-120$ | $6$ | $6$ || $120-130$ | $25$ | $31$ || $130-140$ | $48$ | $79$ || $140-150$ | $72$ | $151$ || $150-160$ | $116$ | $267$ || $160-170$ | $60$ | $327$ || $170-180$ | $38$ | $365$ || $180-190$ | $22$ | $387$ || $190-200$ | $3$ | $390$ |Total frequency $N = 390$. So,$N/2 = 390/2 = 195$.The cumulative frequency just greater than $195$ is $267$,which corresponds to the class interval $150-160$.Thus,the median class is $150-160$.Here,lower limit $l = 150$,frequency of median class $f = 116$,cumulative frequency of the class preceding the median class $cf = 151$,and class size $h = 10$.Using the median formula: $	ext{Median} = l + \left( \frac{N/2 - cf}{f} ight) 	imes h$$	ext{Median} = 150 + \left( \frac{195 - 151}{116} ight) 	imes 10$$	ext{Median} = 150 + \left( \frac{44}{116} ight) 	imes 10 = 150 + \frac{440}{116} \approx 150 + 3.79 = 153.79$.

Marks	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Number of students	$2$	$4$	$7$	$6$	$1$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$
Frequency	$5$	$12$	$18$	$40$	$15$	$7$	$3$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$6$	$f_1$	$20$	$15$	$f_2$	$4$

Class	$12.5-17.5$	$17.5-22.5$	$22.5-27.5$	$27.5-32.5$	$32.5-37.5$
Frequency	$2$	$22$	$19$	$14$	$13$

Find the median of the following frequency distribution:

Class Frequency $(f)$

$110-120$ $6$

$120-130$ $25$

$130-140$ $48$

$140-150$ $72$

$150-160$ $116$

$160-170$ $60$

$170-180$ $38$

$180-190$ $22$

$190-200$ $3$

Similar Questions

Calculate the mean of the scores of $20$ students in a mathematics test:

Marks $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

Number of students $2$ $4$ $7$ $6$ $1$

Find the mean,median and mode of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$

Frequency $5$ $12$ $18$ $40$ $15$ $7$ $3$

The mean of the following frequency distribution is $28.5$ and the total frequency is $60$. Find the missing frequencies $f_{1}$ and $f_{2}$.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

Frequency $6$ $f_1$ $20$ $15$ $f_2$ $4$

For the calculations of mode of a grouped data,the maximum frequency of a class is denoted by $\ldots \ldots \ldots . .$

Construct the cumulative frequency distribution of the following distribution:

Class $12.5-17.5$ $17.5-22.5$ $22.5-27.5$ $27.5-32.5$ $32.5-37.5$

Frequency $2$ $22$ $19$ $14$ $13$

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Class	Frequency $(f)$
$110-120$	$6$
$120-130$	$25$
$130-140$	$48$
$140-150$	$72$
$150-160$	$116$
$160-170$	$60$
$170-180$	$38$
$180-190$	$22$
$190-200$	$3$

Find the median of the following frequency distribution: Class Frequency $(f)$ $110-120$ $6$ $120-130$ $25$ $130-140$ $48$ $140-150$ $72$ $150-160$ $116$ $160-170$ $60$ $170-180$ $38$ $180-190$ $22$ $190-200$ $3$