Find the modulation index of an AM wave havin | vedclass

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(A) The modulation index $m$ is defined as $m = \frac{A_m}{A_c}$,where $A_m$ is the amplitude of the modulating signal and $A_c$ is the amplitude of t

Vedclass · Accepted Answer

$0.8$

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(A) The modulation index $m$ is defined as $m = \frac{A_m}{A_c}$,where $A_m$ is the amplitude of the modulating signal and $A_c$ is the amplitude of the carrier wave.Given the variation in amplitude is $2A_m = 8\,V$,we find $A_m = 4\,V$.The maximum amplitude of the $AM$ wave is given by $A_{max} = A_c + A_m = 9\,V$.Substituting $A_m = 4\,V$,we get $A_c + 4 = 9$,which implies $A_c = 5\,V$.Therefore,the modulation index is $m = \frac{4}{5} = 0.8$.

Find the modulation index of an $AM$ wave having $8\,V$ variation where maximum amplitude of the $AM$ wave is $9\,V$.

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