Class 12Chemistry8-2.Carboxylic acids and Their derivativeMix Examples-Carboxylic acids and Their derivative
DifficultMatch the reactions given in Column-$I$ with their names in Column-$II$.
Column-$I$ (Reaction)
Column-$II$ (Name)
$A$. $RCH_2COOH \rightarrow[H_2O]{X_2/P} RCH(X)COOH$
$i$. Decarboxylation
$B$. $RCOONa \rightarrow[NaOH, CaO, \Delta]{\text{soda lime}} RH$
$ii$. Grignard reaction
$C$. $RCOOH + R'OH \leftrightarrow{H^{+}} RCOOR' + H_2O$
$iii$. Hell-Volhard-Zelinsky reaction
$D$. $RMgX + R'CHO \rightarrow{H_3O^{+}} RCH(OH)R'$
$iv$. Esterification
| Column-$I$ (Reaction) | Column-$II$ (Name) |
|---|---|
| $A$. $RCH_2COOH \rightarrow[H_2O]{X_2/P} RCH(X)COOH$ | $i$. Decarboxylation |
| $B$. $RCOONa \rightarrow[NaOH, CaO, \Delta]{\text{soda lime}} RH$ | $ii$. Grignard reaction |
| $C$. $RCOOH + R'OH \leftrightarrow{H^{+}} RCOOR' + H_2O$ | $iii$. Hell-Volhard-Zelinsky reaction |
| $D$. $RMgX + R'CHO \rightarrow{H_3O^{+}} RCH(OH)R'$ | $iv$. Esterification |
(A-III, B-I, C-IV, D-II) The correct matches are as follows:
$A$. $RCH_2COOH \rightarrow[H_2O]{X_2/P} RCH(X)COOH$ is the Hell-Volhard-Zelinsky reaction $(iii)$.
$B$. $RCOONa \rightarrow[NaOH, CaO, \Delta]{\text{soda lime}} RH$ is Decarboxylation $(i)$.
$C$. $RCOOH + R'OH \leftrightarrow{H^{+}} RCOOR' + H_2O$ is Esterification $(iv)$.
$D$. $RMgX + R'CHO \rightarrow{H_3O^{+}} RCH(OH)R'$ is a Grignard reaction $(ii)$.
Therefore,the correct sequence is $A-iii, B-i, C-iv, D-ii$.
$A$. $RCH_2COOH \rightarrow[H_2O]{X_2/P} RCH(X)COOH$ is the Hell-Volhard-Zelinsky reaction $(iii)$.
$B$. $RCOONa \rightarrow[NaOH, CaO, \Delta]{\text{soda lime}} RH$ is Decarboxylation $(i)$.
$C$. $RCOOH + R'OH \leftrightarrow{H^{+}} RCOOR' + H_2O$ is Esterification $(iv)$.
$D$. $RMgX + R'CHO \rightarrow{H_3O^{+}} RCH(OH)R'$ is a Grignard reaction $(ii)$.
Therefore,the correct sequence is $A-iii, B-i, C-iv, D-ii$.
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Similar Questions
Match the reactions given in Column-$I$ with their products in Column-$II$.
Column-$I$ (Reactant) Column-$II$ (Product) $A$. $RCH_2OH \xrightarrow[(ii) H_3O^{+}]{(i) NaOH, KMnO_4} ?$ $i$. $C_6H_5COOH + C_2H_5OH$ $B$. $CH_3(CH_2)_8CH_2OH \xrightarrow{Jones reagent} ?$ $ii$. $RCOOH$ $C$. $RCONH_2 \xrightarrow{H_3O^{+}, \Delta} ?$ $iii$. $CH_3(CH_2)_8COOH$ $D$. $C_6H_5COOEt \xrightarrow{H_3O^{+}} ?$ $iv$. $RCOOH + NH_3$
| Column-$I$ (Reactant) | Column-$II$ (Product) |
| $A$. $RCH_2OH \xrightarrow[(ii) H_3O^{+}]{(i) NaOH, KMnO_4} ?$ | $i$. $C_6H_5COOH + C_2H_5OH$ |
| $B$. $CH_3(CH_2)_8CH_2OH \xrightarrow{Jones reagent} ?$ | $ii$. $RCOOH$ |
| $C$. $RCONH_2 \xrightarrow{H_3O^{+}, \Delta} ?$ | $iii$. $CH_3(CH_2)_8COOH$ |
| $D$. $C_6H_5COOEt \xrightarrow{H_3O^{+}} ?$ | $iv$. $RCOOH + NH_3$ |
Difficult
View Solution$CH_3CH_2COOH$ $\xrightarrow{P_2O_5}$ $X$ $\xrightarrow{H_2O}$ $Y$ $\xrightarrow{SOCl_2}$ $Z$
Identify $X$,$Y$ and $Z$.
Identify $X$,$Y$ and $Z$.
DifficultTS EAMCET 2015
View SolutionThe product $(C)$ of the above reaction is:
Select the reaction with an incorrect name.
Medium
View SolutionCompound $A$ was treated with a large excess of $CH_3MgBr$. The resulting product was exposed to $POCl_3$ /pyridine to give compound $B$,as one of many products.
Which of the following compounds can be $A$ ?
Which of the following compounds can be $A$ ?
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