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(A) The molar mass of urea $(NH_2CONH_2)$ is $14 + 2(1) + 12 + 16 + 14 + 2(1) = 60 \ g/mol$. Moles of urea $= \frac{	ext{Given mass}}{	ext{Molar mas

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$2.4 	imes 10^{23}$

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(A) The molar mass of urea $(NH_2CONH_2)$ is $14 + 2(1) + 12 + 16 + 14 + 2(1) = 60 \ g/mol$. Moles of urea $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{6.0 \ g}{60 \ g/mol} = 0.1 \ mol$. Each molecule of urea contains $4$ hydrogen atoms. Therefore,moles of $H$-atoms $= 0.1 \ mol 	imes 4 = 0.4 \ mol$. Number of hydrogen atoms $= 	ext{moles} 	imes N_A = 0.4 	imes 6.022 	imes 10^{23} = 2.4088 	imes 10^{23} \approx 2.4 	imes 10^{23}$.

Find the number of hydrogen atoms present in $6.0 \ g$ of urea $(NH_2CONH_2)$:

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