(C) The number of moles is calculated using the formula: $\text{Moles} = \frac{\text{Mass in grams}}{\text{Molar mass}}$Given mass $= 6.9 \times 10^{-

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(C) The number of moles is calculated using the formula: $\text{Moles} = \frac{\text{Mass in grams}}{\text{Molar mass}}$Given mass $= 6.9 \times 10^{-2} \ kg = 6.9 \times 10^{-2} \times 10^3 \ g = 69 \ g$Molar mass of sodium $= 23 \ g \ mol^{-1}$Number of moles $= \frac{69 \ g}{23 \ g \ mol^{-1}} = 3 \ mol$

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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Find the number of moles of sodium atoms in $6.9 \times 10^{-2} \ kg$ (Atomic mass $= 23 \ g \ mol^{-1}$)

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A
$1.5$
B
$0.3$
C
$3$
D
$2.3$

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The mole concept

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Find the number of moles of sodium atoms in $6.9 \times 10^{-2} \ kg$ (Atomic mass $= 23 \ g \ mol^{-1}$)

Similar Questions

One atom of an element weighs $3.32 \times 10^{-23} \ g$. How many gram atoms are there in $20 \ kg$ of the element?

If we take $44 \ g$ of $CO_2$ and $14 \ g$ of $N_2$,what will be the mole fraction of $CO_2$ in the mixture?

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If $10^{21}$ molecules are removed from $200 \ mg$ of $CO_2$,then the number of moles of $CO_2$ left are .......... $\times 10^{-3}$.

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