Find the pressure of neon gas having density | vedclass

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(B) The ideal gas equation is given by $PV = nRT$. Since $n = \frac{m}{M}$,we have $PV = \frac{m}{M} RT$. Rearranging for pressure $P$,we get $P = \fr

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$1.309$

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(B) The ideal gas equation is given by $PV = nRT$. Since $n = \frac{m}{M}$,we have $PV = \frac{m}{M} RT$. Rearranging for pressure $P$,we get $P = \frac{m}{V} 	imes \frac{RT}{M} = \frac{dRT}{M}$. Here,density $d = 0.9 \ g \ L^{-1}$,$R = 8.34 	imes 10^{-2} \ bar \ L \ K^{-1} \ mol^{-1}$,$T = 350 \ K$,and the molar mass of neon $M = 20.18 \ g \ mol^{-1}$. Substituting the values: $P = \frac{0.9 	imes 8.34 	imes 10^{-2} 	imes 350}{20.18} \approx 1.309 \ bar$.

Find the pressure of neon gas having density $0.9 \ g \ L^{-1}$ at $350 \ K$ temperature. $(R = 8.34 \times 10^{-2} \ bar \ L \ K^{-1} \ mol^{-1})$ (in $bar$)

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