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Question

(A) The isocyanide test is a characteristic reaction for primary $(1^{\circ})$ amines. When a primary amine is heated with chloroform $(CHCl_3)$ and a

Vedclass · Accepted Answer

Benzamide + $LiAlH_4$ $\rightarrow$ Product

Vedclass · Answer

(A) The isocyanide test is a characteristic reaction for primary $(1^{\circ})$ amines. When a primary amine is heated with chloroform $(CHCl_3)$ and alcoholic potassium hydroxide $(KOH)$,it forms an isocyanide (carbylamine),which has a characteristic foul smell.$1$. In option $A$,benzamide $(C_6H_5CONH_2)$ reacts with $LiAlH_4$ (a strong reducing agent) to form benzylamine $(C_6H_5CH_2NH_2)$,which is a primary amine and thus gives a positive isocyanide test.$2$. $NaBH_4$ is a weaker reducing agent and does not reduce amides to amines.$3$. $N$-phenylacetamide $(C_6H_5NHCOCH_3)$ is a secondary amide; its reduction would yield a secondary amine,which does not give the isocyanide test.Therefore,the correct reaction is benzamide with $LiAlH_4$.

Find the reaction in which the obtained product gives a positive isocyanide test.

Similar Questions

Which of the following amines forms a clear solution when treated with benzene sulphonyl chloride and excess of potassium hydroxide?

Which of the following compounds gives the carbylamine reaction?

$p-$chloroaniline and anilinium hydrochloride can be distinguished by

Assertion: Benzene diazonium chloride does not give a test for nitrogen.
Reason: Loss of $N_2$ gas takes place during heating.

Which of the following amine$(s)$ show$(s)$ positive carbylamine test?
$A. CH_3CH_2NH_2$
$B. (CH_3)_2NH$
$C. CH_3NH_2$
$D. (CH_3)_3N$
$E. C_6H_5NH_2$
Choose the correct answer from the options given below:

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