જો $Z = \frac{A^{4} B^{1/3}}{C D^{3/2}}$ હોય,તો $Z$ માં સાપેક્ષ ત્રુટિ શોધો.

• A
  $\frac{\Delta Z}{Z} = 4\frac{\Delta A}{A} + \frac{1}{3}\frac{\Delta B}{B} + \frac{\Delta C}{C} + \frac{3}{2}\frac{\Delta D}{D}$
• B
  $\frac{\Delta Z}{Z} = 4\frac{\Delta A}{A} + \frac{1}{3}\frac{\Delta B}{B} - \frac{\Delta C}{C} - \frac{3}{2}\frac{\Delta D}{D}$
• C
  $\frac{\Delta Z}{Z} = 4\frac{\Delta A}{A} - \frac{1}{3}\frac{\Delta B}{B} + \frac{\Delta C}{C} - \frac{3}{2}\frac{\Delta D}{D}$
• D
  $\frac{\Delta Z}{Z} = \frac{\Delta A}{A} + \frac{\Delta B}{B} + \frac{\Delta C}{C} + \frac{\Delta D}{D}$