Find the second order derivative of the funct | vedclass

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Question

(B) Let $y = x^{2} + 3x + 2$. First,differentiate with respect to $x$: $\frac{dy}{dx} = \frac{d}{dx}(x^{2}) + \frac{d}{dx}(3x) + \frac{d}{dx}(2) = 2x

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Let $y = x^{2} + 3x + 2$. First,differentiate with respect to $x$: $\frac{dy}{dx} = \frac{d}{dx}(x^{2}) + \frac{d}{dx}(3x) + \frac{d}{dx}(2) = 2x + 3$. Now,differentiate again with respect to $x$ to find the second order derivative: $\frac{d^{2}y}{dx^{2}} = \frac{d}{dx}(2x + 3) = \frac{d}{dx}(2x) + \frac{d}{dx}(3) = 2 + 0 = 2$. Thus,the second order derivative is $2$.

Find the second order derivative of the function $f(x) = x^{2} + 3x + 2$.

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