Find the solution of the linear equation $x + 2y = 8$ which represents a point on:
$(i)$ $x$-axis
$(ii)$ $y$-axis

(N/A) We know that any point lying on the $x$-axis has its ordinate (y-coordinate) equal to $0$.
Putting $y = 0$ in the equation $x + 2y = 8$,we get:
$x + 2(0) = 8 \Rightarrow x = 8$.
Thus,the point on the $x$-axis is $(8, 0)$.
We also know that any point lying on the $y$-axis has its abscissa (x-coordinate) equal to $0$.
Putting $x = 0$ in the equation $x + 2y = 8$,we get:
$0 + 2y = 8 \Rightarrow 2y = 8 \Rightarrow y = 4$.
Thus,the point on the $y$-axis is $(0, 4)$.