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Question

(A) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the parent chain is a heptanoic acid

Vedclass · Accepted Answer

$2-$Bromo$-7-$hydroxy$-5-$oxoheptanoic acid

Vedclass · Answer

(A) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the parent chain is a heptanoic acid derivative,and the carbon of $-COOH$ is $C-1$.$2$. Number the chain: Starting from the carboxylic acid carbon as $C-1$,the chain is numbered as follows: $C-1$ $(-COOH)$,$C-2$ $(-CHBr)$,$C-3$ $(-CH_2)$,$C-4$ $(-CH_2)$,$C-5$ $(C=O)$,$C-6$ $(-CH_2)$,$C-7$ $(-CH_2OH)$.$3$. Identify substituents and their positions: There is a bromo group at $C-2$,an oxo group at $C-5$,and a hydroxy group at $C-7$.$4$. Assemble the name: Alphabetical order for substituents is Bromo,Hydroxy,Oxo. Thus,the name is $2-$Bromo$-7-$hydroxy$-5-$oxoheptanoic acid.

Find the suitable $IUPAC$ name of the compound given below.

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