Find the value of cos left(-1710^{circ}right) | vedclass

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(A) We know that the value of $\cos(x)$ repeats after an interval of $2\pi$ or $360^{\circ}$.Therefore,$\cos \left(-1710^{\circ}\right) = \cos \left(-

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) We know that the value of $\cos(x)$ repeats after an interval of $2\pi$ or $360^{\circ}$.Therefore,$\cos \left(-1710^{\circ}ight) = \cos \left(-1710^{\circ} + n 	imes 360^{\circ}ight)$.To find the smallest positive angle coterminal with $-1710^{\circ}$,we add multiples of $360^{\circ}$:$-1710^{\circ} + 5 	imes 360^{\circ} = -1710^{\circ} + 1800^{\circ} = 90^{\circ}$.Thus,$\cos \left(-1710^{\circ}ight) = \cos(90^{\circ})$.Since $\cos(90^{\circ}) = 0$,the value is $0$.

Find the value of $\cos \left(-1710^{\circ}\right)$.

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