Find the value of the following polynomial at the indicated value of the variable: $p(t) = 4t^4 + 5t^3 - t^2 + 6$ at $t = a$.
(N/A) Given the polynomial $p(t) = 4t^4 + 5t^3 - t^2 + 6$.
To find the value of the polynomial at $t = a$,we substitute $a$ for $t$ in the expression.
$p(a) = 4(a)^4 + 5(a)^3 - (a)^2 + 6$.
Therefore,the value of the polynomial at $t = a$ is $4a^4 + 5a^3 - a^2 + 6$.
To find the value of the polynomial at $t = a$,we substitute $a$ for $t$ in the expression.
$p(a) = 4(a)^4 + 5(a)^3 - (a)^2 + 6$.
Therefore,the value of the polynomial at $t = a$ is $4a^4 + 5a^3 - a^2 + 6$.
Explore More
Similar Questions
Factorise the following: $64 a^{3}-27 b^{3}-144 a^{2} b+108 a b^{2}$
Easy
View SolutionUse suitable identities to find the products: $(3x + 4)(3x - 5)$
Easy
View SolutionEvaluate the following product without multiplying directly: $95 \times 96$
Medium
View SolutionVerify whether the following is a zero of the polynomial indicated against it:
$p(x) = x^{2}, \, x = 0$
$p(x) = x^{2}, \, x = 0$
Easy
View SolutionVerify whether the following are zeroes of the polynomial indicated against them:
$p(x) = (x + 1)(x - 2)$,$x = -1, 2$
$p(x) = (x + 1)(x - 2)$,$x = -1, 2$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo