Find the value of spin-only magnetic moment f | vedclass

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(B) The electronic configuration of $Cr$ is $[Ar] \ 3d^5 \ 4s^1$.For $Cr^{2+}$,two electrons are removed,resulting in the configuration $[Ar] \ 3d^4$.

Vedclass · Accepted Answer

$4.90$

Vedclass · Answer

(B) The electronic configuration of $Cr$ is $[Ar] \ 3d^5 \ 4s^1$.For $Cr^{2+}$,two electrons are removed,resulting in the configuration $[Ar] \ 3d^4$.The number of unpaired electrons $(n)$ is $4$.The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$.Substituting $n=4$: $\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90 \ BM$.

Find the value of spin-only magnetic moment for chromium cation in $+2$ state. (in $BM$)

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