Find the zero of the polynomial in the following case:
$q(y) = \pi y + 3.14$
$q(y) = \pi y + 3.14$
(N/A) To find the zero of the polynomial $q(y)$,we set $q(y) = 0$.
So,$\pi y + 3.14 = 0$.
Subtracting $3.14$ from both sides,we get $\pi y = -3.14$.
Dividing both sides by $\pi$,we get $y = -\frac{3.14}{\pi}$.
Thus,the zero of the polynomial is $-\frac{3.14}{\pi}$.
So,$\pi y + 3.14 = 0$.
Subtracting $3.14$ from both sides,we get $\pi y = -3.14$.
Dividing both sides by $\pi$,we get $y = -\frac{3.14}{\pi}$.
Thus,the zero of the polynomial is $-\frac{3.14}{\pi}$.
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