Class 12Mathematics3 and 4 .Determinants and MatricesExpansion of determinants, Solution of equation in the form of determinants and area of triangle and Equation of Line
Easy$x$ ની કિંમતો શોધો જેના માટે $\left|\begin{array}{ll}3 & x \\ x & 1\end{array}\right|=\left|\begin{array}{ll}3 & 2 \\ 4 & 1\end{array}\right|$ થાય.
- A$x=\pm 2 \sqrt{2}$
- B$x=\pm 3 \sqrt{2}$
- C$x=\pm \sqrt{2}$
- D$x=\pm 4 \sqrt{2}$
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$\left|\begin{array}{ccc}\frac{-bc}{a^2} & \frac{c}{a} & \frac{b}{a} \\ \frac{c}{b} & \frac{-ac}{b^2} & \frac{a}{b} \\ \frac{b}{c} & \frac{a}{c} & \frac{-ab}{c^2}\end{array}\right| = $
જો $\left|\begin{array}{cc}x & 2 \\ 18 & x\end{array}\right|=\left|\begin{array}{cc}6 & 2 \\ 18 & 6\end{array}\right|,$ હોય,તો $x$ ની કિંમત શોધો.
Easy
View Solutionનિશ્ચાયકનું મૂલ્ય શોધો: $\left|\begin{array}{ccc}0 & 1 & 2 \\ -1 & 0 & -3 \\ -2 & 3 & 0\end{array}\right|$
Easy
View Solutionજો $A_{\lambda} = \begin{bmatrix} \lambda & \lambda - 1 \\ \lambda - 1 & \lambda \end{bmatrix}; \lambda \in N$ હોય,તો $|A_1| + |A_2| + \dots + |A_{300}|$ ની કિંમત શોધો.
જો સમીકરણોની સંહતિ $ax + y + z = 0$,$x + by + z = 0$ અને $x + y + cz = 0$,જ્યાં $a, b, c \neq 1$ હોય,ને શૂન્યેતર ઉકેલ હોય,તો $\frac{1}{1 - a} + \frac{1}{1 - b} + \frac{1}{1 - c}$ ની કિંમત શોધો.
Medium
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