(D) Let the present ages of the four persons be $x_1, x_2, x_3,$ and $x_4$.Five years ago,their ages were $(x_1 - 5), (x_2 - 5), (x_3 - 5),$ and $(x_4

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(D) Let the present ages of the four persons be $x_1, x_2, x_3,$ and $x_4$.Five years ago,their ages were $(x_1 - 5), (x_2 - 5), (x_3 - 5),$ and $(x_4 - 5)$.According to the problem,the sum of their ages five years ago was $60$ years:$(x_1 - 5) + (x_2 - 5) + (x_3 - 5) + (x_4 - 5) = 60$$(x_1 + x_2 + x_3 + x_4) - 20 = 60$$x_1 + x_2 + x_3 + x_4 = 60 + 20$$x_1 + x_2 + x_3 + x_4 = 80$Thus,the sum of their present ages is $80$ years.

Class 10 Mathematics Pair of Linear Equations in Two Variables Mix Examples - Pair of Linear Equations in Two Variables

Medium

Five years ago,the sum of the ages of four persons was $60$ years. The sum of the present ages of those four persons is $\ldots \ldots \ldots \ldots$ years.

A
$100$
B
$70$
C
$65$
D
$80$

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Pair of Linear Equations in Two Variables

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Mix Examples - Pair of Linear Equations in Two Variables

Find the value$(s)$ of $p$ for the equations $-3x + 5y = 7$ and $2px - 3y = 1$ if the lines represented by these equations intersect at a unique point.

Difficult

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Use the method of elimination to find the solution of the following pair of linear equations: $\frac{x}{4} + \frac{y}{3} = 2, 4x + 3y = 25$.

Medium

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Solve the following pair of linear equations by the method of substitution: $x + 8y = 19$ and $2x + 11y = 28$.

Medium

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Write a pair of linear equations which has the unique solution $x = -1, y = 3$. How many such pairs can you write?

Difficult

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From the equation $2x + 3y = 8$,we get $y = \ldots$

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Five years ago,the sum of the ages of four persons was $60$ years. The sum of the present ages of those four persons is $\ldots \ldots \ldots \ldots$ years.

Similar Questions

Find the value$(s)$ of $p$ for the equations $-3x + 5y = 7$ and $2px - 3y = 1$ if the lines represented by these equations intersect at a unique point.

Use the method of elimination to find the solution of the following pair of linear equations: $\frac{x}{4} + \frac{y}{3} = 2, 4x + 3y = 25$.

Solve the following pair of linear equations by the method of substitution: $x + 8y = 19$ and $2x + 11y = 28$.

Write a pair of linear equations which has the unique solution $x = -1, y = 3$. How many such pairs can you write?

From the equation $2x + 3y = 8$,we get $y = \ldots$

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