Fluorine reacts with dilute NaOH and forms a | vedclass

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Question

(B) The reaction of fluorine with dilute $NaOH$ is given by: $2F_2 + 2NaOH \rightarrow 2NaF + OF_2 + H_2O$ Thus,the gaseous product $A$ is oxygen difl

Vedclass · Accepted Answer

$103^{\circ}$

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(B) The reaction of fluorine with dilute $NaOH$ is given by: $2F_2 + 2NaOH \rightarrow 2NaF + OF_2 + H_2O$ Thus,the gaseous product $A$ is oxygen difluoride $(OF_2)$. In $OF_2$,the central oxygen atom is $sp^3$ hybridized with two bond pairs and two lone pairs. Due to the high electronegativity of fluorine atoms,the lone pair-lone pair repulsion is significant,which compresses the bond angle. The bond angle in $OF_2$ is $103^{\circ}$.

Fluorine reacts with dilute $NaOH$ and forms a gaseous product $A$. The bond angle in the molecule of $A$ is

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