Following are the four molecules P,Q,R and S. | vedclass

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(B) The reaction of alkenes with $HBr_{(aq)}$ proceeds via an electrophilic addition mechanism,where the rate-determining step involves the formation

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$Q$

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(B) The reaction of alkenes with $HBr_{(aq)}$ proceeds via an electrophilic addition mechanism,where the rate-determining step involves the formation of a carbocation intermediate.Greater stability of the carbocation intermediate leads to a faster reaction rate.In molecule $Q$,the protonation of the double bond leads to a carbocation that is stabilized by resonance from the lone pair of the adjacent oxygen atom (forming an oxocarbenium ion).This resonance stabilization makes the carbocation derived from $Q$ significantly more stable than the alkyl carbocations formed from $P$,$R$,or $S$.Therefore,molecule $Q$ reacts at the fastest rate.

Following are the four molecules $P$,$Q$,$R$ and $S$. Which one among the four molecules will react with $HBr_{(aq)}$ at the fastest rate?

Similar Questions

Which of the following compounds does not evolve $CO_2$ gas when it undergoes oxidative ozonolysis?

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$1.$ $CH_3-CH_2-CH(N^{+}(CH_3)_3)OH^{-} \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$
$2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$

Which of the following is the most stable?

Which one is an unsaturated compound?

In which of the following reactions will $CO_2$ gas $NOT$ be released?

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