The following diagram performs the logic func | vedclass

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(B) The given circuit consists of two $NAND$ gates connected in series.Let the inputs to the first $NAND$ gate be $A$ and $B$. The output of the first

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$AND$ gate

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(B) The given circuit consists of two $NAND$ gates connected in series.Let the inputs to the first $NAND$ gate be $A$ and $B$. The output of the first $NAND$ gate is $X = \overline{A \cdot B}$.This output $X$ acts as the input to the second $NAND$ gate. Since both inputs of the second $NAND$ gate are connected to $X$, its output $Y$ is given by $Y = \overline{X \cdot X} = \overline{X}$.Substituting the value of $X$, we get $Y = \overline{(\overline{A \cdot B})} = A \cdot B$.The expression $Y = A \cdot B$ represents the logic function of an $AND$ gate.Therefore, the given circuit performs the function of an $AND$ gate.

$A$	$B$	Output
$1$	$0$	$1$
$1$	$1$	$0$
$0$	$1$	$1$
$0$	$0$	$0$

The following diagram performs the logic function of:

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