The following logic gate circuit is connected | vedclass

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(B) The bulb will glow if there is a potential difference across it. This means one end of the bulb must be at a high potential $(1)$ and the other en

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$A=1, B=0, C=0, D=0$

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(B) The bulb will glow if there is a potential difference across it. This means one end of the bulb must be at a high potential $(1)$ and the other end must be at a low potential $(0)$.Let $X$ be the output of the first $NOR$ gate,$Y$ be the output of the $NAND$ gate,and $Z$ be the output of the final $NOR$ gate connected to the resistor.$X = \overline{A+A} = \overline{A}$$Y = \overline{B \cdot C}$$Z = \overline{X+Y} = \overline{\overline{A} + \overline{B \cdot C}} = A \cdot (B \cdot C) = A \cdot B \cdot C$Let $W$ be the output of the bottom $NOR$ gate: $W = \overline{D+D} = \overline{D}$.The bulb glows if the potential difference between $Z$ and $W$ is $1$,i.e.,$(Z=1, W=0)$ or $(Z=0, W=1)$.Checking option $(B)$: $A=1, B=0, C=0, D=0$.$Z = 1 \cdot 0 \cdot 0 = 0$$W = \overline{0} = 1$Since $Z=0$ and $W=1$,there is a potential difference,so the bulb will glow.

The following logic gate circuit is connected in a suitable arrangement. For which of the following combinations will the bulb glow $(ON)$?

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