For 3d_{z^2} calculate the value of n, ell, m | vedclass

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(B) For the orbital $3d_{z^2}$:$1$. The principal quantum number $n$ is given by the coefficient,so $n = 3$.$2$. For a $d$-orbital,the azimuthal quant

Vedclass · Accepted Answer

$n = 3, \ell = 2, m = 0, s = +\frac{1}{2} 	ext{ or } -\frac{1}{2}$

Vedclass · Answer

(B) For the orbital $3d_{z^2}$:$1$. The principal quantum number $n$ is given by the coefficient,so $n = 3$.$2$. For a $d$-orbital,the azimuthal quantum number $\ell = 2$.$3$. The magnetic quantum number $m$ for $d_{z^2}$ is $0$.$4$. The spin quantum number $s$ can be either $+\frac{1}{2}$ or $-\frac{1}{2}$ for any electron.Thus,the correct values are $n = 3, \ell = 2, m = 0, s = +\frac{1}{2} 	ext{ or } -\frac{1}{2}$.

For $3d_{z^2}$ calculate the value of $n, \ell, m$ and $s$.

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