For F_2 and OF molecules,consider the followi | vedclass

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(A) $1$. For $F_2$ ($18$ electrons): Electronic configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 =

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(A) $1$. For $F_2$ ($18$ electrons): Electronic configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$. Bond order = $(10-8)/2 = 1$. It is diamagnetic.$2$. For $OF$ ($17$ electrons): Electronic configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$. Bond order = $(10-7)/2 = 1.5$. It is paramagnetic.$3$. Statement $(a)$: False,as bond order of $F_2$ is $1$ and $OF$ is $1.5$.$4$. Statement $(b)$: True,$OF$ is paramagnetic and $F_2$ is diamagnetic.$5$. Statement $(c)$: True,$F_2$ has a lower bond order $(1)$ compared to $OF$ $(1.5)$,making it easier to dissociate.$6$. Statement $(d)$: True,for both,$BMO$ electrons $(10)$ > $ABMO$ electrons ($8$ for $F_2$,$7$ for $OF$).

List-$I$	List-$II$
$(1)$ ${\rm{NO}}$	$(A)$ $1.5$
$(2)$ ${\rm{CO}}$	$(B)$ $2.0$
$(3)$ ${\rm{O}}_2^-$	$(C)$ $2.5$
$(4)$ ${\rm{O}}_2$	$(D)$ $3.0$

Similar Questions

Number of molecules/species from the following having one unpaired electron: $O_2, O_2^{-}, NO, CN^{-}, O_2^{2-}$

Match the species given in List-$I$ with their bond orders given in List-$II$.

List-$I$ List-$II$

$(1)$ ${\rm{NO}}$ $(A)$ $1.5$

$(2)$ ${\rm{CO}}$ $(B)$ $2.0$

$(3)$ ${\rm{O}}_2^-$ $(C)$ $2.5$

$(4)$ ${\rm{O}}_2$ $(D)$ $3.0$

Which of the following species absorbs maximum energy in its $HOMO-LUMO$ electronic transition?

According to "molecular orbital theory",which among the following diatomic molecules only has $\pi$-bonds?

Which of the following species has the highest bond order?

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