For 0.1 M solutions of the following electro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Colligative properties are directly proportional to the van't Hoff factor $(i)$ for solutions of the same concentration.$1.$ For $NaCl$: $NaCl 	o

Vedclass · Accepted Answer

$NaCl < Na_2SO_4 < Na_3PO_4$

Vedclass · Answer

(B) Colligative properties are directly proportional to the van't Hoff factor $(i)$ for solutions of the same concentration.$1.$ For $NaCl$: $NaCl 	o Na^{+} + Cl^{-}$,so $i = 2$.$2.$ For $Na_2SO_4$: $Na_2SO_4 	o 2Na^{+} + SO_4^{2-}$,so $i = 3$.$3.$ For $Na_3PO_4$: $Na_3PO_4 	o 3Na^{+} + PO_4^{3-}$,so $i = 4$.Since the colligative property depends on the number of particles,the order is $NaCl < Na_2SO_4 < Na_3PO_4$ $(2 < 3 < 4)$.

For $0.1 \ M$ solutions of the following electrolytes,the colligative property will follow the order:

Similar Questions

The freezing point of one molal $NaCl$ solution,assuming $NaCl$ to be $100\%$ dissociated in water,is ............ $^oC$. (molal depression constant $= 1.86$)

For very dilute solutions of $BaCl_2$ $(t_1)$ and $KCl$ $(t_2)$ having the same molarity,what is the correct relationship between their boiling points?

$1 \ mol$ each of the following compounds is dissolved in $1 \ L$ of solution. Which will have the largest $\Delta T_b$ value?

Which of the following aqueous solutions has the highest boiling point?

The Van't Hoff factor of $Ca(NO_3)_2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module