For y = log_a x to be defined,a must be: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The logarithmic function $y = \log_a x$ is defined under the following conditions:$1$. The base $a$ must be a positive real number,i.e.,$a > 0$.$2

Vedclass · Accepted Answer

Any positive real number $a 
eq 1$

Vedclass · Answer

(D) The logarithmic function $y = \log_a x$ is defined under the following conditions:$1$. The base $a$ must be a positive real number,i.e.,$a > 0$.$2$. The base $a$ cannot be equal to $1$,i.e.,$a 
eq 1$.$3$. The argument $x$ must be positive,i.e.,$x > 0$.Therefore,for the expression to be defined,$a$ must be any positive real number except $1$.

For $y = \log_a x$ to be defined,$a$ must be:

Similar Questions

The equivalent function of $\log {x^2}$ is

If $\sqrt{\log_3 x^{16}} + 9 \log_{27} \sqrt[3]{\frac{3}{x}} = 5$,then $x = \dots$.

Let $x$ and $y$ be real numbers such that $x > 2y > 0$ and $2 \log (x - 2y) = \log x + \log y$. Then,the possible value$(s)$ of $\frac{x}{y}$ is/are:

The number of solution$(s)$ of the equation $\ln(\ln x) = \log_x e$ is -

If $a < 1$ and $2 \operatorname{Sinh}^{-1}\left(\frac{a}{\sqrt{1-a^2}}\right)=\log \left(\frac{1+x}{1-x}\right)$,then $x=$

Vedclass Test Series

Exam Paper Generator

Online Exam Module