For $n \in N$,if $A_n = \cos \left(\frac{\pi}{2^n}\right) + i \sin \left(\frac{\pi}{2^n}\right)$,then $(A_1 A_2 A_3 A_4)^4 =$

  • A
    $\frac{-1-i}{\sqrt{2}}$
  • B
    $1$
  • C
    $0$
  • D
    $\frac{1-i}{\sqrt{2}}$

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