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(D) According to Raoult's law, the relative lowering of vapour pressure is equal to the mole fraction of the solute.$\frac{P^o - P_s}{P^o} = X_{	ext{

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$0.8$

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(D) According to Raoult's law, the relative lowering of vapour pressure is equal to the mole fraction of the solute.$\frac{P^o - P_s}{P^o} = X_{	ext{solute}}$Given that the vapour pressure decreases by $20 \%$, the lowering of vapour pressure is $\frac{P^o - P_s}{P^o} = 0.2$.Therefore, the mole fraction of the solute $X_{	ext{solute}} = 0.2$.Since the sum of mole fractions in a binary solution is $1$, we have $X_{	ext{solvent}} + X_{	ext{solute}} = 1$.$X_{	ext{solvent}} = 1 - 0.2 = 0.8$.

For a binary solution, when a nonvolatile nonelectrolyte solute is dissolved in a solvent, the vapour pressure of the solvent decreases by $20 \%$. What is the mole fraction of the solvent in the solution?

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