For a continuous series,the mode is computed | vedclass

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Question

(C) The formula for calculating the mode for a continuous frequency distribution is given by: $Mode = l + \left( \frac{f_m - f_{m-1}}{2f_m - f_{m-1} -

Vedclass · Accepted Answer

$l + \frac{f_m - f_{m-1}}{2f_m - f_{m-1} - f_{m+1}} 	imes C$ or $l + \frac{f_m - f_1}{2f_m - f_1 - f_2} 	imes i$

Vedclass · Answer

(C) The formula for calculating the mode for a continuous frequency distribution is given by: $Mode = l + \left( \frac{f_m - f_{m-1}}{2f_m - f_{m-1} - f_{m+1}} ight) 	imes C$ where: $l$ is the lower limit of the modal class,$f_m$ is the frequency of the modal class,$f_{m-1}$ is the frequency of the class preceding the modal class,$f_{m+1}$ is the frequency of the class succeeding the modal class,$C$ (or $i$) is the width of the class interval. Thus,option $C$ is correct.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
$f_i$	$2$	$18$	$30$	$45$	$35$	$20$	$6$	$3$

Class	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$a$	$b$	$12$	$9$	$5$

For a continuous series,the mode is computed by the formula:

Similar Questions

The mode of the following data set is $0, 1, 6, 7, 2, 3, 7, 6, 6, 2, 6, 0, 5, 6, 0$.

Find the mode of the given frequency distribution.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

$f_i$ $2$ $18$ $30$ $45$ $35$ $20$ $6$ $3$

If for a slightly asymmetric distribution,mean and median are $5$ and $6$ respectively,what is its mode?

Consider the following frequency distribution:

Class $0-6$ $6-12$ $12-18$ $18-24$ $24-30$

Frequency $a$ $b$ $12$ $9$ $5$

If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$

In a given frequency distribution,the respective values of mean and median are $21$ and $22$. The value of mode is

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