For a gas,frac{R}{C_{v}}=0.4,where R is the u | vedclass

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(A) Given: $\frac{R}{C_v} = 0.4$ $C_V = \frac{R}{0.4} = \frac{R}{2/5} = \frac{5R}{2}$ We know that for an ideal gas,$C_P = C_V + R$. Substituting the

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rigid diatomic.

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(A) Given: $\frac{R}{C_v} = 0.4$ $C_V = \frac{R}{0.4} = \frac{R}{2/5} = \frac{5R}{2}$ We know that for an ideal gas,$C_P = C_V + R$. Substituting the value of $C_V$: $C_P = \frac{5R}{2} + R = \frac{7R}{2}$ The adiabatic index $\gamma$ is given by $\gamma = \frac{C_P}{C_V}$. $\gamma = \frac{7R/2}{5R/2} = \frac{7}{5} = 1.4$. For a rigid diatomic gas,the degrees of freedom $f = 5$. The molar specific heat at constant volume is $C_V = \frac{fR}{2} = \frac{5R}{2}$. Since the calculated $C_V$ matches the value for a rigid diatomic gas,the gas is made up of rigid diatomic molecules.

For a gas,$\frac{R}{C_{v}}=0.4$,where $R$ is the universal gas constant and $C_{v}$ is the molar specific heat at constant volume. The gas is made up of molecules which are

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