For a given material, the Young's modulus is | vedclass

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(A) The relationship between Young's modulus $(Y)$, modulus of rigidity $(\eta)$, and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 2\eta(1

Vedclass · Accepted Answer

$0.2$

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(A) The relationship between Young's modulus $(Y)$, modulus of rigidity $(\eta)$, and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 2\eta(1 + \sigma)$.Given that the Young's modulus is $2.4$ times its modulus of rigidity, we have: $Y = 2.4\eta$.Equating the two expressions for $Y$:$2.4\eta = 2\eta(1 + \sigma)$Divide both sides by $2\eta$:$1.2 = 1 + \sigma$Solving for $\sigma$:$\sigma = 1.2 - 1 = 0.2$.Therefore, the Poisson's ratio is $0.2$.

For a given material, the Young's modulus is $2.4$ times its modulus of rigidity. Its Poisson's ratio is ......

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