For a given medium, the polarizing angle is 6 | vedclass

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Question

(A) The relationship between the polarizing angle $(i_p)$ and the refractive index $(\mu)$ is given by Brewster's Law: $\mu = 	an i_p$.Given $i_p = 6

Vedclass · Accepted Answer

$\sin^{-1}(0.577)$

Vedclass · Answer

(A) The relationship between the polarizing angle $(i_p)$ and the refractive index $(\mu)$ is given by Brewster's Law: $\mu = 	an i_p$.Given $i_p = 60^o$, we have $\mu = 	an 60^o = \sqrt{3} \approx 1.732$.The critical angle $(i_c)$ is related to the refractive index by the formula: $\sin i_c = \frac{1}{\mu}$.Substituting the value of $\mu$: $\sin i_c = \frac{1}{\sqrt{3}} = \frac{1}{1.732} \approx 0.577$.Therefore, the critical angle is $i_c = \sin^{-1}(0.577)$.

For a given medium, the polarizing angle is $60^o$. What will be the critical angle for this medium?

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