For a projectile,the maximum height and horizontal range are same. The angle of projection $\theta$ of the projectile is

The equations of motion of a projectile are given by $x = 36t$ metre and $2y = 96t - 9.8t^2$ metre. The angle of projection is:

$A$ ball is projected from the ground with a speed $15 \, m/s$ at an angle $\theta$ with the horizontal such that its range and maximum height are equal. Then,$\tan \theta$ will be equal to:

$A$ projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of $3 \, ms^{-2}$ for $0.5 \, minutes$. If the maximum height reached by it is $80 \, m$,then the angle of projection is (Take $g = 10 \, ms^{-2}$)

$A$ missile is fired for maximum range at your town from a place $100 \, km$ away from you. If the missile is first detected at its half-way point,how much warning time will you have? (Take $g = 10 \, m/s^2$). What was the speed of the missile when it was detected?

Two spheres are projected at angles $30^{\circ}$ and $45^{\circ}$ with the horizontal. The maximum height reached by both is same. The ratio of their initial velocities is, $(\sin 45^{\circ} = \frac{1}{\sqrt{2}}, \sin 30^{\circ} = 0.5)$