For a purely inductive or a purely capacitive circuit,the power factor is

$A$ capacitor '$C$' is connected across a $DC$ source,the reactance of the capacitance will be . . . . . . .

$A$ sinusoidal voltage $V(t) = 100 \sin(500t)$ is applied across a pure inductance of $L = 0.02 \, H$. The current through the coil is:

In an a.c. circuit with pure capacitance $C$ and a.c. source $E = E_0 \sin \omega t$, the equation of instantaneous current is given by

An $AC$ alternating $emf$ $E = 110 \sqrt{2} \sin(100t) \text{ V}$ is applied to a capacitor of $2 \mu F$. The $rms$ value of current in the circuit is $...... \text{ mA}$.

An alternating voltage given as $V = 100 \sqrt{2} \sin(100t) \text{ V}$ is applied to a capacitor of $1 \mu\text{F}$. The current reading of the ammeter will be equal to . . . . . . $\text{mA}$.