For a reaction frac{1}{2} A rightarrow 2B, th | vedclass

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(B) For a general reaction $aA \rightarrow bB$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = \frac{1}{b} \frac{d[B]}{dt}$ G

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$-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

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(B) For a general reaction $aA \rightarrow bB$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = \frac{1}{b} \frac{d[B]}{dt}$ Given the reaction $\frac{1}{2} A \rightarrow 2B$,we have $a = \frac{1}{2}$ and $b = 2$. Substituting these values into the rate expression: $-\frac{1}{1/2} \frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$ $-2 \frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$ Dividing both sides by $2$: $-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

For a reaction $\frac{1}{2} A \rightarrow 2B,$ the rate of disappearance of $A$ is related to the rate of appearance of $B$ by the expression:

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