For a reaction if K_p K_c,the forward react | vedclass

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(A) The relationship between $K_p$ and $K_c$ is given by $K_p = K_c(RT)^{\Delta n}$.Given that $K_p > K_c$,it implies that $(RT)^{\Delta n} > 1$,which

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Low pressure

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(A) The relationship between $K_p$ and $K_c$ is given by $K_p = K_c(RT)^{\Delta n}$.Given that $K_p > K_c$,it implies that $(RT)^{\Delta n} > 1$,which means $\Delta n > 0$.$\Delta n$ represents the change in the number of moles of gaseous products minus the number of moles of gaseous reactants.Since $\Delta n > 0$,the number of moles of gaseous products is greater than the number of moles of gaseous reactants.According to Le Chatelier's principle,for a reaction where the number of moles of gas increases,decreasing the pressure will shift the equilibrium in the forward direction to increase the number of moles and counteract the pressure change.Therefore,the forward reaction is favoured by low pressure.

For a reaction if $K_p > K_c$,the forward reaction is favoured by

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