For a single electron system,the following gr | vedclass

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(D) The number of radial nodes in an orbital is given by the formula $(n - l - 1)$.For $1s$ orbital: $n=1, l=0$,radial nodes $= 1 - 0 - 1 = 0$.For $2p

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The graph must be representing an orbital different from $2s$

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(D) The number of radial nodes in an orbital is given by the formula $(n - l - 1)$.For $1s$ orbital: $n=1, l=0$,radial nodes $= 1 - 0 - 1 = 0$.For $2p$ orbital: $n=2, l=1$,radial nodes $= 2 - 1 - 1 = 0$.For $3d$ orbital: $n=3, l=2$,radial nodes $= 3 - 2 - 1 = 0$.The given graph shows zero radial nodes because the $RDF$ curve touches the x-axis only at $r=0$ and $r=\infty$.Since all $1s, 2p,$ and $3d$ orbitals have zero radial nodes,the graph could represent any of these orbitals.However,looking at the options,$A, B,$ and $C$ are specific,while $D$ states it is different from $2s$ (which has $1$ radial node). Since the graph has $0$ radial nodes,it is indeed different from $2s$. Given the nature of such questions,if multiple options are technically correct,we look for the most encompassing one. However,usually,these questions have a single best fit. Since $1s, 2p, 3d$ all have $0$ nodes,they all fit the graph. Option $D$ is a true statement as the graph cannot be $2s$.

For a single electron system,the following graph is drawn for the radial distribution function $(RDF)$ versus radial distance. The correct statement regarding the graph is:

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