For a transformer,the turns ratio is $3$ and its efficiency is $0.75$. The current flowing in the primary coil is $2 \,A$ and the voltage applied to it is $100 \,V$. Then the voltage and the current flowing in the secondary coil are ... respectively.

$A$ small town with a demand of $900 \text{ kW}$ of electric power at $220 \text{ V}$ is situated $20 \text{ km}$ away from an electric power generating station. The two-wire line has a resistance per unit length of $5 \times 10^{-4} \text{ } \Omega \text{ m}^{-1}$. The town gets power from the line through a $45000 \text{ V}$ to $220 \text{ V}$ step-down transformer at a substation in the town. The line power loss in the form of heat is: (in $text{ kW}$)

The alternating voltage induced in the secondary coil of a transformer is mainly due to

$A$ power transmission line feeds input power at $2300 \ V$ to a step-down transformer with its primary winding having $4000$ turns. What should be the number of turns in the secondary in order to get output power at $230 \ V$?

$A$ step-down transformer has a $N_{S}$ to $N_{P}$ ratio of $1: 20$. If $8 \, V$ are developed across a $0.4 \, \Omega$ secondary load, the primary current will be: (in $ \, A$)

If a step-up transformer has a turn ratio of $5$,a frequency of $50 \, Hz$,the root mean square $(RMS)$ value of the potential difference on the primary is $100 \, V$,and the resistance of the secondary winding is $500 \, \Omega$,then the peak value of the voltage in the secondary winding will be (the efficiency of the transformer is $100 \%$).