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(C) Given,the current amplification factor $\alpha = 0.8$.For a common emitter configuration,the current gain $\beta$ is related to $\alpha$ by the fo

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$24$

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(C) Given,the current amplification factor $\alpha = 0.8$.For a common emitter configuration,the current gain $\beta$ is related to $\alpha$ by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Substituting the value of $\alpha$: $\beta = \frac{0.8}{1 - 0.8} = \frac{0.8}{0.2} = 4$.The relationship between the change in collector current $\Delta i_c$ and the change in base current $\Delta i_b$ is given by $\Delta i_c = \beta 	imes \Delta i_b$.Given $\Delta i_b = 6 \, mA$,we have $\Delta i_c = 4 	imes 6 \, mA = 24 \, mA$.

For a transistor,the current amplification factor $\alpha$ is $0.8$. The transistor is connected in a common emitter configuration. The change in the collector current when the base current changes by $6 \, mA$ is ..... $mA$.

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