(D) In a common emitter configuration,the current gain $A_i$ is given by the formula:$A_i = \frac{-h_{fe}}{1 + h_{oe} R_L}$Given:$h_{fe} = 50$$h_{oe}

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(D) In a common emitter configuration,the current gain $A_i$ is given by the formula:$A_i = \frac{-h_{fe}}{1 + h_{oe} R_L}$Given:$h_{fe} = 50$$h_{oe} = 25 \ \mu A/V = 25 \times 10^{-6} \ S$$R_L = 1 \ k\Omega = 10^3 \ \Omega$Substituting the values:$A_i = \frac{-50}{1 + (25 \times 10^{-6}) \times 10^3}$$A_i = \frac{-50}{1 + 0.025}$$A_i = \frac{-50}{1.025}$$A_i \approx -48.78$

Class 12 Physics Semiconductor Electronics Junction Transistor

Medium

For a transistor amplifier in common emitter configuration with a load impedance of $1 \ k\Omega$ ($h_{fe} = 50$ and $h_{oe} = 25 \ \mu A/V$),the current gain is:

AIEEE 2004 All AIEEE

A
$-5.2$
B
$-15.7$
C
$-24.8$
D
$-48.78$

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For a transistor amplifier in common emitter configuration with a load impedance of $1 \ k\Omega$ ($h_{fe} = 50$ and $h_{oe} = 25 \ \mu A/V$),the current gain is:

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