(B) The current gain $\beta_{dc}$ for a common-emitter transistor configuration is defined as the ratio of the collector current $(i_c)$ to the base c

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collector current to base current

(B) The current gain $\beta_{dc}$ for a common-emitter transistor configuration is defined as the ratio of the collector current $(i_c)$ to the base current $(i_b)$.Mathematically,$\beta_{dc} = \frac{i_c}{i_b} = \frac{\text{Collector current}}{\text{Base current}}$.

Class 12 Physics Semiconductor Electronics Junction Transistor

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For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

MHT CET 2019 All MHT CET

A
collector current to emitter current
B
collector current to base current
C
base current to collector current
D
emitter current to collector current

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Assertion: In a transistor,the base is made thin.
Reason: $A$ thin base makes the transistor stable.

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In the case of constants $\alpha$ and $\beta$ of a transistor:

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For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

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Assertion: In a transistor,the base is made thin.Reason: $A$ thin base makes the transistor stable.

In a common base circuit of a transistor,the amplification factor is $0.95.$ The base current when the emitter current is $2\,mA,$ is ....$mA$

In a $PNP$ transistor working as a common-base amplifier,current gain is $0.96$ and emitter current is $7.2 \, mA$. The base current is.....$mA$

Input signal to a common emitter amplifier having a voltage gain of $1000$ is given by $v_i = (0.004 \, V) \sin(\omega t + \pi/2)$. The corresponding output signal is

In the case of constants $\alpha$ and $\beta$ of a transistor:

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Assertion: In a transistor,the base is made thin.
Reason: $A$ thin base makes the transistor stable.