For a zero order reaction,a plot of t_{1/2} v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a zero order reaction:Rate $= K[A]^0 = K$Integrating the rate law,$[A]_t = [A]_0 - Kt$.At half-life $(t = t_{1/2})$,the concentration $[A]_t =

Vedclass · Accepted Answer

$A$ straight line passing through the origin and slope $= 1/(2K)$

Vedclass · Answer

(D) For a zero order reaction:Rate $= K[A]^0 = K$Integrating the rate law,$[A]_t = [A]_0 - Kt$.At half-life $(t = t_{1/2})$,the concentration $[A]_t = [A]_0/2$.Substituting these values: $[A]_0/2 = [A]_0 - K t_{1/2}$.Rearranging gives $K t_{1/2} = [A]_0/2$,or $t_{1/2} = \frac{[A]_0}{2K}$.Comparing this with the equation of a straight line $y = mx + c$,where $y = t_{1/2}$,$x = [A]_0$,and $m = 1/(2K)$,the plot of $t_{1/2}$ versus $[A]_0$ is a straight line passing through the origin with a slope of $1/(2K)$.

For a zero order reaction,a plot of $t_{1/2}$ versus $[A]_0$ will be

Similar Questions

If $c_o$ is the initial concentration of the reactant,what will be the half-life period for a zero-order reaction?

What is a zero order reaction? Determine the integrated rate equation for a zero order reaction $R \to P$.

What is the unit of $K$ for a zero-order reaction?

$2A \xrightarrow{k} B$ is a zero-order reaction, where $k = 1.0 \text{ mol L}^{-1} \text{ min}^{-1}$. If the initial concentration of $A$ is $2 \text{ M}$, then the time taken to complete $75\%$ of the reaction will be (in $\text{ min}$)

If the rate constant $(K)$ of a reaction is $1.6 \times 10^{-3} \ mol \ L^{-1} \ min^{-1}$,the order of reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module