For the chemical reactions shown below,identi | vedclass

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(A) The reaction of cyclohexene with $KMnO_4 / H_2SO_4 / \Delta$ (hot acidic $KMnO_4$) causes oxidative cleavage of the double bond,resulting in the f

Vedclass · Accepted Answer

Compound '$A$' is a dicarboxylic acid and compound '$B$' is a diol.

Vedclass · Answer

(A) The reaction of cyclohexene with $KMnO_4 / H_2SO_4 / \Delta$ (hot acidic $KMnO_4$) causes oxidative cleavage of the double bond,resulting in the formation of a dicarboxylic acid (adipic acid) as compound '$A$'.The reaction of cyclohexene with $KMnO_4 / H_2O / 273 \ K$ (cold alkaline $KMnO_4$,also known as Baeyer's reagent) results in syn-hydroxylation,forming a diol (cyclohexane$-1,2-$diol) as compound '$B$'.Therefore,compound '$A$' is a dicarboxylic acid and compound '$B$' is a diol.

For the chemical reactions shown below,identify the correct statement from the following:

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