For all positive integers $k$, if the greatest divisor of $25^k+12k-1$ is $d$, then $4\sqrt{d}=$

  • A
    $36$
  • B
    $8$
  • C
    $20$
  • D
    $24$

Explore More

Similar Questions

For a positive integer $n$, $n^{3} + 2n$ is always divisible by

The product of the last two digits of $(1919)^{1919}$ is . . . . . . .

If $n \in N$,then ${x^{2n - 1}} + {y^{2n - 1}}$ is divisible by

If $k \in N$,then $3^{3k} - 26k - 1$ is divisible by

The remainder left when $8^{2n} - 62^{2n+1}$ is divided by $9$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo