For an alternating current I = I_0 cos(omega | vedclass

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(B) The given equation for the alternating current is $I = I_0 \cos(\omega t)$.Comparing this with the standard form $I = I_{peak} \cos(\omega t)$,the

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$\frac{I_0}{\sqrt{2}}, I_0$

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(B) The given equation for the alternating current is $I = I_0 \cos(\omega t)$.Comparing this with the standard form $I = I_{peak} \cos(\omega t)$,the peak value of the current is $I_{peak} = I_0$.The root mean square $(rms)$ value of an alternating current is defined as $I_{rms} = \frac{I_{peak}}{\sqrt{2}}$.Substituting the value of $I_{peak}$,we get $I_{rms} = \frac{I_0}{\sqrt{2}}$.Therefore,the $rms$ value is $\frac{I_0}{\sqrt{2}}$ and the peak value is $I_0$.

For an alternating current $I = I_0 \cos(\omega t)$,what is the $rms$ value and peak value of the current?

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