For any A.P.,T_{25} - T_{20} = ldots ldots ld | vedclass

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Question

(A) The $n^{th}$ term of an $A.P.$ is given by the formula $T_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.For $T_{2

Vedclass · Accepted Answer

$5d$

Vedclass · Answer

(A) The $n^{th}$ term of an $A.P.$ is given by the formula $T_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.For $T_{25}$,we have $T_{25} = a + (25 - 1)d = a + 24d$.For $T_{20}$,we have $T_{20} = a + (20 - 1)d = a + 19d$.Now,calculating the difference: $T_{25} - T_{20} = (a + 24d) - (a + 19d)$.$T_{25} - T_{20} = a + 24d - a - 19d = 5d$.Therefore,the correct option is $A$.

For any $A.P.$,$T_{25} - T_{20} = \ldots \ldots \ldots$

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