For a hydrogen atom,the energy of an electron | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a hydrogen atom,the total energy $(E)$ of an electron in a given orbit is related to its kinetic energy $(KE)$ by the relation: $E = -KE$.Give

Vedclass · Accepted Answer

$34$

Vedclass · Answer

(A) For a hydrogen atom,the total energy $(E)$ of an electron in a given orbit is related to its kinetic energy $(KE)$ by the relation: $E = -KE$.Given that the energy of the electron in the first excited state is $-3.4 \ eV$,we have $E = -3.4 \ eV$.Therefore,the kinetic energy is $KE = -E = -(-3.4 \ eV) = 3.4 \ eV$.We are given $KE = x \ eV$,so $x = 3.4$.We need to express $x$ in the form $x 	imes 10^{-1} \ eV$.$3.4 = 34 	imes 10^{-1}$.Thus,the value of $x$ is $34$.

For a hydrogen atom,the energy of an electron in the first excited state is $-3.4 \ eV$. The kinetic energy $(KE)$ of the same electron in the hydrogen atom is $x \ eV$. The value of $x$ is . . . . . . $\times 10^{-1} \ eV$. (Nearest integer)

Similar Questions

Electrons with a kinetic energy of $6.023 \times 10^4 \ J/mol$ are evolved from the surface of a metal when it is exposed to radiation of wavelength $600 \ nm$. The minimum amount of energy required to remove an electron from the metal atom is

Which of the following was $NOT$ proposed by Rutherford in his atomic model?

What is the maximum wavelength line in the Lyman series of $He^{+}$ ion?

The total number of spectral lines observed when an electron returns from the $6^{th}$ shell to the $2^{nd}$ shell in a hydrogen atom is:

Angular momentum of an electron in the second shell of a $Li^{+2}$ ion is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module