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(C) In an interference pattern, the intensity of the resultant wave is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$.For bright fringes, $\cos

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equal

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(C) In an interference pattern, the intensity of the resultant wave is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$.For bright fringes, $\cos \phi = 1$, so $I_{max} = I_1 + I_2 + 2\sqrt{I_1 I_2} = (\sqrt{I_1} + \sqrt{I_2})^2$.For dark fringes, $\cos \phi = -1$, so $I_{min} = I_1 + I_2 - 2\sqrt{I_1 I_2} = (\sqrt{I_1} - \sqrt{I_2})^2$.Contrast is defined by the visibility of fringes, which is maximum when $I_{min} = 0$.Setting $I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2 = 0$ gives $\sqrt{I_1} = \sqrt{I_2}$, which implies $I_1 = I_2$.Therefore, the intensities of the two coherent sources must be equal to obtain maximum contrast.

For obtaining maximum contrast between the bright and dark fringes in an interference pattern, the intensities of the two light coherent sources should be

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