For skywave propagation of a 10, MHz signal,w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The critical frequency $f_c$ for skywave propagation is related to the maximum electron density $N_{max}$ in the ionosphere by the formula: $f_c =

Vedclass · Accepted Answer

$\sim 1.2 	imes 10^{12}\, m^{-3}$

Vedclass · Answer

(A) The critical frequency $f_c$ for skywave propagation is related to the maximum electron density $N_{max}$ in the ionosphere by the formula: $f_c = 9(N_{max})^{1/2}$,where $f_c$ is in $Hz$ and $N_{max}$ is in $m^{-3}$.Given $f_c = 10\, MHz = 10^7\, Hz$.Substituting the values: $10^7 = 9 	imes (N_{max})^{1/2}$.$(N_{max})^{1/2} = \frac{10^7}{9} \approx 1.11 	imes 10^6$.Squaring both sides: $N_{max} = (1.11 	imes 10^6)^2 \approx 1.23 	imes 10^{12}\, m^{-3}$.Thus,the minimum electron density required is approximately $1.2 	imes 10^{12}\, m^{-3}$.

For skywave propagation of a $10\, MHz$ signal,what should be the minimum electron density in the ionosphere?

Similar Questions

If $y = \log_e \tan \left(\frac{\pi}{4} + \frac{x}{2}\right)$,then $\tanh \left(\frac{y}{2}\right) = $

A capacitor $C$ is first charged fully with potential difference of $V_{0}$ and disconnected from the battery. The charged capacitor is connected across an inductor having inductance $L$. In time $t$, $25 \%$ of the initial energy in the capacitor is transferred to the inductor. The value of $t$ is

If $|x| < \frac{1}{2}$,then the coefficient of $x^r$ in the expansion of $\frac{1+2x}{(1-2x)^2}$ is

The metal used for the de-bromination reaction of $1, 2-dibromoethane$ is:

Why does molten sodium chloride conduct electricity?

Vedclass Test Series

Exam Paper Generator

Online Exam Module